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If A is a square matrix of order 3 and ∣A∣=4|A| = 4, then the value of ∣2AT∣|2A^T| is

Solution

✅ Correct Option: 4

Given that AA is a square matrix of order 3 and ∣A∣=4|A| = 4.

The order 3 means AA is a 3×33 \times 3 matrix.


For the transpose property:

∣AT∣=∣A∣|A^T| = |A|

Therefore:

∣AT∣=4|A^T| = 4


When a matrix is multiplied by a scalar kk, the determinant follows:

∣kA∣=kn×∣A∣|kA| = k^n \times |A|

where nn is the order of the matrix.


For ∣2AT∣|2A^T| where k=2k = 2 and n=3n = 3:

∣2AT∣=23×∣AT∣|2A^T| = 2^3 \times |A^T|

∣2AT∣=8×4|2A^T| = 8 \times 4

∣2AT∣=32|2A^T| = 32

Therefore, the value of ∣2AT∣=32|2A^T| = 32.

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