CUET Mathematics - Match List-I with List-II | List-I | List-II | |---|---| | Differential equation | Order and degree | | (A) (y''')^3 + (y')^4 - 6 = (y''')^2 | (I) Order = 1, Degree = 2 | | (B) sqrt((y')^2 + 5) = y'' | (II) Order = 2, Degree = 3 | | (C) (y')^2 = (2 + y'')^3/2 | (III) Order = 2, Degree = 2 | | (D) y = xy' + sqrt(a^2(y')^2 + b^2) | (IV) Order = 3, Degree = 2 | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2025 15 May Shift 2

Calculus

Medium

common

(A) - (II), (B) - (III), (C) - (IV), (D) - (I)

(A) - (IV), (B) - (I), (C) - (III), (D) - (II)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (IV), (B) - (I), (C) - (II), (D) - (III)

✅ Correct Option: 3

Related questions:

13 May Shift 2

Match List-I with List-II

Let $f: A o B$ be a function given by $f(x) = x^2$

List-I	List-II
Differential equation	Degree
(A) $\frac{d^2y}{dx^2} + \sqrt{\frac{dy}{dx}} - y = 0$	(I) 6
(B) $\sqrt{\frac{d^4y}{dx^4}} + \sqrt[3]{\frac{d^3y}{dx^3}} = 0$	(II) Not defined
(C) $\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} + e^{\frac{dx}{dx}} = x^2$	(III) 3
(D) $\sqrt{\frac{dy}{dx} - \frac{d^2y}{dx^2}} = e^x$	(IV) 2

Choose the correct answer from the options given below:

29 May Shift 2

The number of arbitrary constants in the general solution of a differential equation of order 4 and degree 1 is

15 May Shift 2

The general solution of the differential equation $(x^2 - yx^2)dy + (y^2 + x^2y^2)dx = 0$ is:

CUET Mathematics 2025 15 May Shift 2 PYQs