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An objective function z=ax+byz = ax + by is maximum at points (15,15) and (0, 20). If a,b0a, b \geq 0 and ab=27ab = 27, then the maximum value of the objective function is

Solution

Correct Option: 2

The objective function z=ax+byz = ax + by is maximum at two points: (15,15)(15, 15) and (0,20)(0, 20).

When a linear objective function has maximum value at two different points, both points give the same maximum value. This occurs when the objective function line is parallel to the edge connecting these two points in the feasible region.


Since both points give the same maximum value:

15a+15b=0+20b15a + 15b = 0 + 20b

15a=20b15b15a = 20b - 15b

15a=5b15a = 5b

3a=b3a = b


Using the condition ab=27ab = 27 with b=3ab = 3a:

a×3a=27a \times 3a = 27

3a2=273a^2 = 27

a2=9a^2 = 9

a=3a = 3 (since a0a \geq 0)


From b=3ab = 3a:

b=3×3b = 3 \times 3

b=9b = 9


Using point (15,15)(15, 15):

z=ax+byz = ax + by

z=3(15)+9(15)z = 3(15) + 9(15)

z=45+135z = 45 + 135

z=180z = 180

Therefore, the maximum value of the objective function is 180180.

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