Skip to main contentSkip to solution

The area enclosed between y2=4xy^2 = 4x, x=1x = 1, x=4x = 4 in first quadrant is :

Solution

✅ Correct Option: 1

From y2=4xy^2 = 4x, y=2xy = 2\sqrt{x} in first quadrant. Area =∫142x dx=43[x3/2]14=43(8−1)=283= \int_1^4 2\sqrt{x}\,dx = \frac{4}{3}\left[x^{3/2}\right]_1^4 = \frac{4}{3}(8-1) = \frac{28}{3} sq. units.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question