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The corner points of the feasible region for an L.P.P. are (0,10)(0, 10), (5,5)(5, 5), (5,15)(5, 15) and (0,30)(0, 30). If the objective function is Z=αx+βyZ = \alpha x + \beta y, where α,β>0\alpha, \beta > 0, find the condition on α\alpha and β\beta so that the maximum of ZZ occurs at both the corner points (5,15)(5, 15) and (0,30)(0, 30).

Solution

✅ Correct Option: 3

If the maximum of ZZ occurs at two corner points, then ZZ must have the same value at both of them.

Value of ZZ at the two points:

Z(5,15)=5α+15βZ(5, 15) = 5\alpha + 15\beta

Z(0,30)=30βZ(0, 30) = 30\beta

Equating the two values:

5α+15β=30β5\alpha + 15\beta = 30\beta

5α=15β5\alpha = 15\beta

α=3β\alpha = 3\beta

Verification (taking α=3\alpha = 3, β=1\beta = 1):

Corner PointZ=3x+yZ = 3x + y
(0,10)(0, 10)1010
(5,5)(5, 5)2020
(5,15)(5, 15)3030 ← Maximum
(0,30)(0, 30)3030 ← Maximum

The maximum value 3030 occurs at both (5,15)(5, 15) and (0,30)(0, 30), so the condition holds.

Answer

α=3β\boxed{\alpha = 3\beta}

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