If xsqrt(1+y)+ysqrt(1+x)=0, x≠ y, then dy/dx is equal to Option 1: 1/(1+x)^2 Option 2: 1/1+x^2 Option 3: -1/(1+x)^2 Option 4: 1/1-x^2

The answer is '-1/(1+x)^2'. View full solution:

CUET Mathematics - If xsqrt(1+y)+ysqrt(1+x)=0, x≠ y, then dy/dx is equal to | PYQs + Solutions

CUET Mathematics 2026 14th May Shift 2

Calculus

Medium

core

$\frac{1}{(1+x)^2}$

$\frac{1}{1+x^2}$

$-\frac{1}{(1+x)^2}$

$\frac{1}{1-x^2}$

✅ Correct Option: 3

Related questions:

22 May Shift 3

Match List - I with List - II.

	List - I		List - II
(A)	$y = \log(\sin x)$	(I)	$\frac{d^2y}{dx^2} = -\frac{1}{x^2}$
(B)	$y = e^{(1 + \log x)}$	(II)	$\frac{d^2y}{dx^2} = 2$
(C)	$y = \log\lvert x \rvert$	(III)	$\frac{d^2y}{dx^2} = 0$
(D)	$y = x^2 + 4x - 1$	(IV)	$\frac{d^2y}{dx^2} = -\csc^2 x$

Choose the correct answer from the options given below :

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If $x^2+y^2 = t+\dfrac{1}{t}$ and $x^4+y^4=t^2+\dfrac{1}{t^2}$ , then $\dfrac{dy}{dx}$ is equal to

29th May Shift 2

A function f(x) is defined by $f(x)=\begin{cases}x^2+\alpha x+\beta: & 0\leq x<2\\3x+2 : & 2\leq x\leq4\\2\alpha x+5\beta :& 4<x\leq8\end{cases}$ . If function f(x) is continuous on [0, 8], then value of $2\alpha+3\beta$ is

CUET Mathematics 2026 14th May Shift 2 PYQs

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