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Which of the following is/are correct?

A. ∫ex[1(x−2)−1(x−2)2]dx=ex(x−2)+C\int e^x\left[\frac{1}{(x-2)}-\frac{1}{(x-2)^2}\right]dx=\frac{e^x}{(x-2)}+C, where C is an arbitrary constant.

B. ∫ex[1(x−2)3−3(x−2)4]dx=ex(x−2)2+C\int e^x\left[\frac{1}{(x-2)^3}-\frac{3}{(x-2)^4}\right]dx=\frac{e^x}{(x-2)^2}+C, where C is an arbitrary constant.

C. ∫ex[x−4(x−2)3]dx=ex(x−2)2+C\int e^x\left[\frac{x-4}{(x-2)^3}\right]dx=\frac{e^x}{(x-2)^2}+C, where C is an arbitrary constant.

D. ∫ex[1x+2−3(x+2)2]dx=ex(x+2)2+C\int e^x\left[\frac{1}{x+2}-\frac{3}{(x+2)^2}\right]dx=\frac{e^x}{(x+2)^2}+C, where C is an arbitrary constant.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

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