CUET Mathematics - Which of the following is/are correct? A. e^x[1/(x-2)-1/(x-2)^2]dx=e^x/(x-2)+C, where C is an arbitrary constant. B. e^x[1/(x-2)^3-3/(x-2)^4]dx=e^x/(x-2)^2+C, where C is an arbitrary constant. C. e^x[x-4/(x-2)^3]dx=e^x/(x-2)^2+C, where C is an arbitrary constant. D. e^x[1/x+2-3/(x+2)^2]dx=e^x/(x+2)^2+C, where C is an arbitrary constant. Choose the correct answer from the options given below: | PYQs + Solutions | AfterBoards

CUET Mathematics 2026 30th May Shift 1 PYQs

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CUET Mathematics 2026 30th May Shift 1

Calculus

>

Hard

common

A, B and D only

A, C and D only

B and C only

A only

✅ Correct Option: 4

Related questions:

29th May Shift 1

$\displaystyle\int \dfrac{xdx}{x^2+3x+2}$ is equal to:

(where $c$ is an arbitrary constant)

22nd May Shift 2

Match List-I with List-II

List-I	List-II
(A) $\int_{-1}^{1} \lvert x \rvert dx =$	(I) 3
(B) $\int_{-\pi}^{\pi} \cos x \, dx =$	(II) 1
(C) $\int_{-1}^{1} (\lvert x \rvert-1) dx =$	(III) 0
(D) $\int_{-1}^{1} (\lvert x \rvert+1) dx =$	(IV) -1

Choose the correct answer from the options given below:

30 Aug Shift 1

$\int x\sqrt{x + 2} \, dx$ is equal to :

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