CUET Mathematics - If x = t^3, y = t^2 then d^2y/d^2x is equal to: | PYQs + Solutions

CUET Mathematics 2025 21 May Shift 2

Calculus

Medium

applied

$\frac{-1}{t^2}$

$\frac{1}{2t^3}$

$\frac{-1}{t^3}$

$\frac{-2}{9t^4}$

✅ Correct Option: 4

Related questions:

30 May Shift 2

If $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ , then $\frac{d^2y}{dx^2}$ is equal to

CUET Mathematics 2024 Slot 1

Choose the correct answer from the options given below :

14 May Shift 2

Match List-I with List-II

List-I	List-II
Function	Derivative
(A) $y = \sin^{-1} x + \sin^{-1} \sqrt{1 - x^2}; \|x\| < 1$	(I) $\frac{dy}{dx} = \frac{1}{2y-1}$
(B) $y = \sqrt{x + y}, x+y > 0 \text{ and } y \neq \frac{1}{2}$	(II) $\frac{dy}{dx} = 10^x \log_e 10$
(C) $y = \log_{10} x, x > 0$	(III) $\frac{dy}{dx} = 0$
(D) $y = 10^x$	(IV) $\frac{dy}{dx} = \frac{1}{x \log_e 10}$

Choose the correct answer from the options given below:

CUET Mathematics 2025 21 May Shift 2 PYQs