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Match List-I with List-II

List-I (Function)List-II (Critical point)
(A) f(x)=x3−3xf(x)=x^3-3x(I) x=3x=3
(B) f(x)=x3−12xf(x)=x^3-12x(II) x=0x=0
(C) f(x)=x2−6xf(x)=x^2-6x(III) x=1x=1
(D) f(x)=x2f(x)=x^2(IV) x=2x=2

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Set f′(x)=0f'(x) = 0 in each case.

(A) 3x2−3=0⇒x=±13x^2-3 = 0 \Rightarrow x = \pm1, so x=1x=1 is listed.

(B) 3x2−12=0⇒x=±23x^2-12 = 0 \Rightarrow x = \pm2, so x=2x=2.

(C) 2x−6=0⇒x=32x-6 = 0 \Rightarrow x = 3.

(D) 2x=0⇒x=02x = 0 \Rightarrow x = 0.

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