The shortest distance between the lines whose vector equations are r=( i+2 j+3 k)+(2 i+3 j+4 k) and r=(2 i+4 j+5 k)+(4 i+6 j+8 k) is: Option 1: 5sqrt(29) Option 2: sqrt(15)sqrt(29) Option 3: sqrt(29)5 Option 4: sqrt(29)sqrt(15)

The answer is '5sqrt(29)'. View full solution:

CUET Mathematics - The shortest distance between the lines whose vector equations are r=( i+2 j+3 k)+(2 i+3 j+4 k) and r=(2 i+4 j+5 k)+(4 i+6 j+8 k) is: | PYQs + Solutions

CUET Mathematics 2026 14th May Shift 2

Geometry

Medium

core

$\frac{\sqrt5}{\sqrt{29}}$

$\frac{\sqrt{15}}{\sqrt{29}}$

$\frac{\sqrt{29}}{\sqrt5}$

$\frac{\sqrt{29}}{\sqrt{15}}$

✅ Correct Option: 1