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Let A=[aij]3×3A=[a_{ij}]_{3\times3}, where aij=i−ja_{ij}=i-j, then which of the following statements is/are TRUE ?

A. A is diagonal matrix

B. A is square matrix

C. A is symmetric matrix

D. A is skew symmetric matrix

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

A=[0−1−210−1210]A=\begin{bmatrix}0&-1&-2\\1&0&-1\\2&1&0\end{bmatrix} is 3×33\times3, hence square (B true). Since aji=j−i=−aija_{ji}=j-i=-a_{ij} and the diagonal is zero, it is skew symmetric (D true). Non-zero off-diagonal entries rule out diagonal, and a12≠a21a_{12}\ne a_{21} rules out symmetric.

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