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If the matrix A=[cos⁡θsin⁡θ−sin⁡θcos⁡θ]A = \begin{bmatrix} \cos\theta & \sin\theta \\ -\sin\theta & \cos\theta \end{bmatrix}, then A2A^2 is equal to:

Solution

✅ Correct Option: 1

AA is a rotation matrix by angle θ\theta. Two rotations of θ\theta compose to a rotation of 2θ2\theta. Direct multiplication confirms each entry uses the double-angle identities, giving cos⁡2θ\cos 2\theta and sin⁡2θ\sin 2\theta in place of cos⁡θ\cos\theta and sin⁡θ\sin\theta.

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