Algebra

Probability

Easy

core

A pair of unbaised dice is thrown together and sum of the numbers appearing is observed. The probability that the sum of numbers on the dice was 10, given that the observed sum was at least 9, is:

$\frac{5}{18}$

$\frac{3}{10}$

$\frac{1}{12}$

✅ Correct Option: 2

Outcomes with sum at least $9$ : four give $9$ , three give $10$ , two give $11$ and one gives $12$ , so $10$ outcomes in all.

Of these, $3$ have sum $10$ , so the conditional probability is $\frac{3}{10}$ .

2023: 22 May Shift 3

The black and red die are rolled. The conditional probability of obtaining a sum greater than 9 given that the black die resulted in a 5 is :

2026: 30 May Shift 2

If two cards are drawn at random without replacement from a pack of 52 playing cards, then the probability that both the cards are red, is

2025: 21 May Shift 1

The mean of the number of heads in a simultaneous toss of three coins is

2025: 22 May Shift 1

Let X denotes the number of doublets obtained in 3 throws of a pair of dice.

Match List-I with List-II

Choose the correct answer from the options given below:

2025: 3 June Shift 2

A random variable X has the following probability distribution:

X	0	1	2
P(X)	1/4	1/2	1/4

then, which of the following is correct?

2022: 23 Aug Shift 1

In the family mother, father and son stand up at random for a family picture. Define following two events :

$E$ = [Son stands at one of the two ends in the picture]

$F$ = [Father stands in the middle of the picture]

The value of $P(F/E)$ is :

Solution