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For an LPP: Maximize z=3x+9yz = 3x + 9y, x≥0,y≥0x \geq 0, y \geq 0, the feasible region OAB is shown in the figure, then the other constraints are

Figure for CUET Mathematics 2025 14 May Shift 2 question 41 (Algebra)

Solution

✅ Correct Option: 4

The Linear Programming Problem requires identifying the missing constraints from the feasible region OAB shown in the graph.

Given information:

Objective function: Maximize z=3x+9yz = 3x + 9y

Basic constraints: x≥0,y≥0x \geq 0, y \geq 0 (first quadrant)

Feasible region: Triangle OAB


From the graph, identify the three vertices of triangle OAB:

O=(0,0)O = (0, 0) (Origin)

A=(0,20)A = (0, 20) (on the y-axis)

B=(20,20)B = (20, 20) (in the first quadrant)

These vertices help us determine the boundary lines.


The feasible region is bounded by three lines. Two are already given: x=0x = 0 (y-axis) and y=0y = 0 (x-axis).

The third boundary is the slanted line passing through A and another point on the x-axis.


From the options, try x+3y=60x + 3y = 60:

When x=0x = 0:

3y=603y = 60

y=20y = 20 ✓ (matches point A)

When y=0y = 0:

x=60x = 60 (gives point (60,0)(60, 0) on x-axis)

Since the feasible region OAB is below this line (towards the origin):

x+3y≤60x + 3y \leq 60


The line through O(0,0)O(0,0) and B(20,20)B(20,20) is found by noting both coordinates are equal.

This line is x=yx = y.

The feasible region OAB lies above or on this line (closer to the y-axis).

Therefore:

x≤yx \leq y


The complete set of constraints is:

x≥0,y≥0x \geq 0, y \geq 0

x+3y≤60x + 3y \leq 60

x≤yx \leq y

The other constraints are x+3y≤60x + 3y \leq 60 and x≤yx \leq y.

Therefore, the answer is Option 4.

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