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The rate of change of area of a circle with respect to its circumference when radius in 6 cm, is

Solution

✅ Correct Option: 3

The rate of change of area with respect to circumference is dAdC\dfrac{dA}{dC} when radius is 6 cm.

For a circle with radius rr:

Area: A=πr2A = \pi r^2

Circumference: C=2πrC = 2\pi r


Using the chain rule:

dAdC=dAdr×drdC\dfrac{dA}{dC} = \dfrac{dA}{dr} \times \dfrac{dr}{dC}


Finding dAdr\dfrac{dA}{dr}:

A=πr2A = \pi r^2

dAdr=2πr\dfrac{dA}{dr} = 2\pi r


Finding drdC\dfrac{dr}{dC}:

C=2πrC = 2\pi r

dCdr=2π\dfrac{dC}{dr} = 2\pi

drdC=12π\dfrac{dr}{dC} = \dfrac{1}{2\pi}


dAdC=dAdr×drdC\dfrac{dA}{dC} = \dfrac{dA}{dr} \times \dfrac{dr}{dC}

dAdC=2πr×12π\dfrac{dA}{dC} = 2\pi r \times \dfrac{1}{2\pi}

dAdC=r\dfrac{dA}{dC} = r


At r=6r = 6 cm:

dAdC=6\dfrac{dA}{dC} = 6 cm

Therefore, the rate of change of area with respect to circumference is 66 cm.

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