CUET Mathematics - Match the LIST-I with LIST-II | | LIST-I | | LIST-II | |---|---|---|---| | A. | Column matrix | I. | bmatrix1 & 2 & 3bmatrix | | B. | Row matrix | II. | bmatrix1 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 3bmatrix | | C. | Diagonal matrix | III. | bmatrix1\\ 2\\ 3bmatrix | | D. | Scalar matrix | IV. | bmatrix2 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 2bmatrix | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 26th May Shift 2

Algebra

Easy

applied

A-III, B-II, C-IV, D-I

A-III, B-IV, C-I, D-II

A-III, B-I, C-II, D-IV

A-III, B-II, C-I, D-IV

✅ Correct Option: 3

Related questions:

21 May Shift 2

Match List-I with List-II

List-I (Matrix A)	List-II (Determinant of Adjoint of A)
(A) $\begin{bmatrix} 3 & 1 \\ 4 & 2 \end{bmatrix}$	(I) 9
(B) $\begin{bmatrix} 5 & -1 \\ 4 & 2 \end{bmatrix}$	(II) 8
(C) $\begin{bmatrix} 6 & -1 \\ 2 & 1 \end{bmatrix}$	(III) 14
(D) $\begin{bmatrix} 4 & 1 \\ 3 & 3 \end{bmatrix}$	(IV) 2

Choose the correct answer from the options given below:

29 May Shift 2

If $x \neq y \neq z$ then $\begin{vmatrix} 1 & x & x^2 \\ 1 & y & y^2 \\ 1 & z & z^2 \end{vmatrix}$ is equal to

29th May Shift 2

If $\begin{vmatrix}x&2\\18&x\end{vmatrix} = \begin{vmatrix}6&2\\18&6\end{vmatrix}$ , then x equals:

CUET Mathematics 2026 26th May Shift 2 PYQs