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If y=xlog⁡e(x2+x)y = x\log_e\left(\dfrac{x}{2+x}\right), then x3d2ydx2x^3\dfrac{d^2y}{dx^2} is equal to:

Solution

✅ Correct Option: 3

Writing y=x(log⁡x−log⁡(2+x))y = x(\log x - \log(2+x)), we get y′=log⁡x2+x+22+xy' = \log\frac{x}{2+x} + \frac{2}{2+x}.

Differentiating again, y′′=2x(2+x)−2(2+x)2=4x(2+x)2y'' = \frac{2}{x(2+x)} - \frac{2}{(2+x)^2} = \frac{4}{x(2+x)^2}.

Hence x3y′′=4x2(2+x)2=(2x2+x)2x^3y'' = \frac{4x^2}{(2+x)^2} = \left(\frac{2x}{2+x}\right)^2.

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