Skip to main contentSkip to solution

Match the LIST-I with LIST-II

[Where R and Z denotes set of real numbers and set of integers respectively]

LIST-I
Function
LIST-II
Nature
A.f:R→R,f(x)=sin⁡2x+cos⁡2xf: R \to R, f(x) = \sin^2 x + \cos^2 xI.Bijective
B.f:Z→Z,f(x)=x3f: Z \to Z, f(x) = x^3II.Surjective but not injective
C.f:R→R,f(x)=x3−xf: R \to R, f(x) = x^3 - xIII.Injective but not surjective
D.f:R→R,f(x)=3−4xf: R \to R, f(x) = 3 - 4xIV.Neither injective nor surjective

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

sin⁡2x+cos⁡2x=1\sin^2x+\cos^2x=1 is constant, so it is neither injective nor surjective (IV). On ZZ, x3x^3 is one-one but misses non-cubes, so injective but not surjective (III). On RR, x3−xx^3-x is onto but repeats values (II). The linear map 3−4x3-4x is bijective (I).

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question