The set of values of x satisfying x12(5) is: (Where I is set of integer) Option 1: \x:x=12+5,\ I\ Option 2: \x:x=5+12,\ I\ Option 3: \x:x=12,\ I\ Option 4: \x:x=1+12,\ I\

Answer: \x:x=12+5,\ I\. Solution: x12±od5 means x-12 is divisible by 5, so x=12+5 for some integer .

Arithmetic

Numericals

Easy

applied

The set of values of $x$ satisfying $x\equiv12(\mod5)$ is: (Where $I$ is set of integer)

$\{x:x=12+5\lambda,\ \lambda\in I\}$

$\{x:x=5+12\lambda,\ \lambda\in I\}$

$\{x:x=12\lambda,\ \lambda\in I\}$

$\{x:x=1+12\lambda,\ \lambda\in I\}$

✅ Correct Option: 1

$x\equiv12\pmod5$ means $x-12$ is divisible by 5, so $x=12+5\lambda$ for some integer $\lambda$ .

2026: 22 May Shift 1

Which of the following holds true?

(A) $26\equiv1(mod\ 5)$

(B) $17\equiv3(mod\ 8)$

(D) $39\equiv12(mod\ 7)$

Choose the correct answer from the options given below:

2025: 14 May Shift 2

The least non-negative remainder when $2^{101}$ is divided by 5 is:

2026: 31 May Shift 2

The value of $m$ satisfying $m \equiv 12(mod\ 7)$ is:

2025: 19 May Shift 1

The unit digit of $12^{12}$ is:

2025: 3 June Shift 2

The least non-negative remainder, when $5^{61}$ is divided by 7, is

2026: 22 May Shift 2

The least non-negative remainder when $3^{2026}$ is divided by 13 is: