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If y=x3log⁡(3x2+6)y = x^3\log(3x^2+6), then dydx=\dfrac{dy}{dx} =

Solution

✅ Correct Option: 3

By the product rule, dydx=3x2log⁡(3x2+6)+x3⋅6x3x2+6\dfrac{dy}{dx} = 3x^2\log(3x^2+6)+x^3\cdot\dfrac{6x}{3x^2+6}.

The second term simplifies to 2x4x2+2\dfrac{2x^4}{x^2+2}.

Taking x2x2+2\dfrac{x^2}{x^2+2} common gives x2x2+2[(3x2+6)log⁡(3x2+6)+2x2]\dfrac{x^2}{x^2+2}\left[(3x^2+6)\log(3x^2+6)+2x^2\right].

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