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A simple random sample of 64 items from a population with standard deviation σ=4\sigma=4 resulted in a sample mean of 35. What is the margin of error for the population mean at a 95% confidence level? (Given Z0.025=1.96Z_{0.025}=1.96)

Solution

✅ Correct Option: 2

Margin of error =Zα/2σn= Z_{\alpha/2}\dfrac{\sigma}{\sqrt n}.

=1.96×464=1.96×0.5=0.98= 1.96 \times \dfrac{4}{\sqrt{64}} = 1.96 \times 0.5 = 0.98.

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