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Let L be the set of all lines in a plane and R be the relation on set L defined by R={(L1,L2):L1⊥L2}R = \{(L_1, L_2): L_1 \perp L_2\} Then R is

(A) an equivalence Relation

(B) a symmetric Relation

(C) not a transitive Relation

(D) a reflexive Relation

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

The set LL contains all lines in a plane. The relation RR connects two lines if they are perpendicular to each other: R={(L1,L2):L1⊥L2}R = \{(L_1, L_2): L_1 \perp L_2\}.

To determine the properties of this relation, checking reflexive, symmetric, transitive, and equivalence properties is required.


A line cannot be perpendicular to itself. Two lines are perpendicular only when they meet at 90°, but a line with itself is the same line (angle = 0°).

Therefore, RR is not reflexive.


If line L1L_1 is perpendicular to line L2L_2, then L2L_2 is also perpendicular to L1L_1. When line 1 makes 90° with line 2, line 2 also makes 90° with line 1.

Therefore, RR is symmetric.


Consider three lines where:

  • L2L_2 is a vertical line
  • L1L_1 is a horizontal line (perpendicular to L2L_2)
  • L3L_3 is also a horizontal line (perpendicular to L2L_2)

Here L1⊥L2L_1 \perp L_2 and L2⊥L3L_2 \perp L_3, but L1L_1 and L3L_3 are parallel, not perpendicular.

Therefore, RR is not transitive.


An equivalence relation requires all three properties: reflexive, symmetric, and transitive.

Since RR is not reflexive and not transitive, RR is not an equivalence relation.


From the analysis:

  • (A) Not an equivalence relation
  • (B) Symmetric relation ✓
  • (C) Not a transitive relation ✓
  • (D) Not a reflexive relation

The correct answer is (B) and (C) only.

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