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Let f:[2,∞)→Rf : [2, \infty) \to \mathbf{R} be a function defined by f(x)=x2−4x+5f(x) = x^2 - 4x + 5. The range of ff is :

Solution

✅ Correct Option: 2

f(x)=(x−2)2+1f(x) = (x-2)^2 + 1. On [2,∞)[2,\infty), minimum is at x=2x=2 giving f(2)=1f(2)=1, and ff increases. Range is [1,∞)[1, \infty).

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