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If x112=49124x^{\frac{1}{12}}=49^{\frac{1}{24}}, the value of xx is:

Solution

✅ Correct Option: 2

Given x112=49124x^{\frac{1}{12}}=49^{\frac{1}{24}}.

Raising both sides to the power of 1212:

(x112)12=(49124)12(x^{\frac{1}{12}})^{12} = (49^{\frac{1}{24}})^{12}


The left side becomes:

(x112)12=x112×12(x^{\frac{1}{12}})^{12} = x^{\frac{1}{12} \times 12}

=x1= x^1

=x= x


The right side becomes:

(49124)12=49124×12(49^{\frac{1}{24}})^{12} = 49^{\frac{1}{24} \times 12}

=491224= 49^{\frac{12}{24}}

=4912= 49^{\frac{1}{2}}


Since 4912=4949^{\frac{1}{2}} = \sqrt{49} and 7×7=497 \times 7 = 49:

4912=749^{\frac{1}{2}} = 7


Therefore, x=7x = 7.

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