20:[["$","title","0",{"children":"BMSAT Kozhikode - If x^1/12=49^1/24, the value of x is: | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined Given x^1/12=49^1/24. Raising both sides to the power of 12: (x^1/12)^12 = (49^1/24)^12

The <=ft side becomes: (x^1/12)^12 = x^1/12 12 = x^1 = x

The right side becomes: (49^1/24)^12 = 49^1/24 12 = 49^12/24 = 49^1/2

Since 49^1/2 = sqrt(49) and 7 7 = 49: 49^1/2 = 7

Therefore, x = 7."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"BMSAT Kozhikode,QA,Algebra,Indices"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"name":"mobile-web-app-capable","content":"yes"}],["$","meta","8",{"name":"apple-mobile-web-app-title","content":"AfterBoards"}],["$","meta","9",{"name":"apple-mobile-web-app-status-bar-style","content":"default"}],["$","meta","10",{"property":"og:title","content":"BMSAT Kozhikode - If x^1/12=49^1/24, the value of x is: | PYQs + Solutions"}],["$","meta","11",{"property":"og:description","content":"undefined Given x^1/12=49^1/24. Raising both sides to the power of 12: (x^1/12)^12 = (49^1/24)^12

The <=ft side becomes: (x^1/12)^12 = x^1/12 12 = x^1 = x

The right side becomes: (49^1/24)^12 = 49^1/24 12 = 49^12/24 = 49^1/2

Since 49^1/2 = sqrt(49) and 7 7 = 49: 49^1/2 = 7

Therefore, x = 7."}],["$","meta","12",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/iimk-bmsat/2025/QA/20"}],["$","meta","13",{"property":"og:site_name","content":"AfterBoards | BMSAT Kozhikode Preparation"}],["$","meta","14",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","15",{"property":"og:type","content":"website"}],["$","meta","16",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","17",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","18",{"name":"twitter:title","content":"BMSAT Kozhikode - If x^1/12=49^1/24, the value of x is: | PYQs + Solutions"}],["$","meta","19",{"name":"twitter:description","content":"undefined Given x^1/12=49^1/24. Raising both sides to the power of 12: (x^1/12)^12 = (49^1/24)^12

The <=ft side becomes: (x^1/12)^12 = x^1/12 12 = x^1 = x

The right side becomes: (49^1/24)^12 = 49^1/24 12 = 49^12/24 = 49^1/2

Since 49^1/2 = sqrt(49) and 7 7 = 49: 49^1/2 = 7

Therefore, x = 7."}],["$","meta","20",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","link","21",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","22",{"rel":"icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],["$","link","23",{"rel":"icon","href":"https://www.afterboards.in/icons/windows11/Square44x44Logo.altform-lightunplated_targetsize-256.png","sizes":"256x256","type":"image/png"}],["$","link","24",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-512-512.png","sizes":"512x512","type":"image/png"}],["$","link","25",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-192-192.png","sizes":"192x192","type":"image/png"}],["$","link","26",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-144-144.png","sizes":"144x144","type":"image/png"}],["$","link","27",{"rel":"icon","href":"https://www.afterboards.in/icons/android/android-launchericon-96-96.png","sizes":"96x96","type":"image/png"}],"$L2e","$L2f"]

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