Q1:

BMSAT Kozhikode 2026

Logarithms

Medium

If log⁡6x+2log⁡36x+3log⁡216x=9\log_6 x + 2\log_{36} x + 3\log_{216} x = 9, then x=x = ___

Answer options
Option 3
Correct Answer
Explanation for BMSAT Kozhikode 2026 QA question 1

Q2:

BMSAT Kozhikode 2025

Logarithms

Easy

If y>0,y > 0, and log⁡y(x)=4,log⁡10y(25x)=2\log_{y}(x) = 4, \log_{10y} (25x) = 2 hold, what is y?y?

Answer options
Option 1
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 2

Q3:

BMSAT Kozhikode 2025

Logarithms

Medium

Simplify the following: 1log⁡8(x)−1log⁡7(x)+1log⁡6(x)−1log⁡5(x)+1log⁡4(x)−1log⁡3(x)+1log⁡2(x)\dfrac{1}{\log_{8}(x)} - \dfrac{1}{\log_{7}(x)} + \dfrac{1}{\log_{6}(x)} - \dfrac{1}{\log_{5}(x)} + \dfrac{1}{\log_{4}(x)} - \dfrac{1}{\log_{3}(x)} + \dfrac{1}{\log_{2}(x)}

Answer options
Option 3
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 3