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If n≤4n \leq 4 and 2≤m≤n≤5,2 \leq m \leq n \leq 5, then what is the greatest possible value of (n−m)(n+m)?(n - m)(n + m)?

Solution

✅ Correct Option: 3

The constraints are:

  • n≤4n \leq 4
  • 2≤m≤n≤52 \leq m \leq n \leq 5

Combining these gives: 2≤m≤n≤42 \leq m \leq n \leq 4


The expression can be simplified:

(n−m)(n+m)=n2−m2(n - m)(n + m) = n^2 - m^2


To maximize n2−m2n^2 - m^2:

  • Maximum value of n2n^2 requires the largest possible nn
  • Minimum value of m2m^2 requires the smallest possible mm

From the constraints:

  • Largest possible n=4n = 4
  • Smallest possible m=2m = 2

Since 2≤4≤42 \leq 4 \leq 4, these values satisfy all constraints.


The maximum value is:

(n−m)(n+m)=n2−m2(n - m)(n + m) = n^2 - m^2

=42−22= 4^2 - 2^2

=16−4= 16 - 4

=12= 12

Therefore, the greatest possible value is 1212.

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