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The diameter of a solid sphere is 6 cm. If the sphere is melted and drawn into a wire of diameter 2 mm, the length of the wire will be

Solution

✅ Correct Option: 4

Sphere diameter = 66 cm, so radius = 33 cm

Wire diameter = 22 mm = 0.20.2 cm, so radius = 0.10.1 cm

When a solid is melted and reshaped, its volume remains constant.


Volume of sphere = 43πr3\dfrac{4}{3}\pi r^3

Volume = 43×π×(3)3\dfrac{4}{3} \times \pi \times (3)^3

Volume = 43×π×27\dfrac{4}{3} \times \pi \times 27

Volume = 36π36\pi cm³


The wire is cylindrical in shape.

Volume of cylinder (wire) = πr2h\pi r^2 h where hh = length of wire

Since volumes are equal:

36π=π×(0.1)2×length36\pi = \pi \times (0.1)^2 \times \text{length}

36π=π×0.01×length36\pi = \pi \times 0.01 \times \text{length}


36π=0.01π×length36\pi = 0.01\pi \times \text{length}

36=0.01×length36 = 0.01 \times \text{length}

length=360.01\text{length} = \dfrac{36}{0.01}

length=3600\text{length} = 3600 cm


Converting to meters: 36003600 cm = 3636 meters

Therefore, the length of the wire will be 36003600 cm or 3636 meters.

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