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If 2x/(1+2x)=1/32^x/(1 + 2^x) = 1/3, then 8x/(1−8x)=?8^x/(1-8^x) = ?

Solution

✅ Correct Option: 3

2x1+2x=13\dfrac{2^x}{1 + 2^x} = \dfrac{1}{3}

3⋅2x=1+2x3 \cdot 2^x = 1 + 2^x

3⋅2x−2x=13 \cdot 2^x - 2^x = 1

2⋅2x=12 \cdot 2^x = 1

2x=122^x = \dfrac{1}{2}


Since 8=238 = 2^3, we can write 8x=(2x)38^x = (2^x)^3

8x=(12)3=188^x = \left(\dfrac{1}{2}\right)^3 = \dfrac{1}{8}


8x1−8x=181−18\dfrac{8^x}{1 - 8^x} = \dfrac{\frac{1}{8}}{1 - \frac{1}{8}}

=1878= \dfrac{\frac{1}{8}}{\frac{7}{8}}

=18×87= \dfrac{1}{8} \times \dfrac{8}{7}

=17= \dfrac{1}{7}

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