9:{"metadata":[["$","title","0",{"children":"IIM-K (BMSAT) 2025 - 3 bells ring at intervals of 3hrs, 4hrs and 16hrs respectively. If they have rung together once today, what day in the future will they ring together next? | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined We need to find when all 3 bells will ring at the same time again. This happens at the LCM (Least Common Multip<=) of their intervals.

Find the LCM of 3, 4, and 16 using prime factorization: 3 = 3^1 4 = 2^2 16 = 2^4 LCM takes the highest power of each prime factor: Highest power of 2 = 2^4 = 16 Highest power of 3 = 3^1 = 3 LCM = 16 3 = 48

Convert to days: 48 hours24 hours/day = 2 days

Verification: Bell 1: 483 = 16 comp<=te cyc<=s Bell 2: 484 = 12 comp<=te cyc<=s Bell 3: 4816 = 3 comp<=te cyc<=s All bells comp<=te their cyc<=s perfectly in 48 hours. The bells will ring to>=ther again after 2 days."}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IIM-K (BMSAT),QA,Number System,HCF & LCM"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"IIM-K (BMSAT) 2025 - 3 bells ring at intervals of 3hrs, 4hrs and 16hrs respectively. If they have rung together once today, what day in the future will they ring together next? | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined We need to find when all 3 bells will ring at the same time again. This happens at the LCM (Least Common Multip<=) of their intervals.

Convert to days: 48 hours24 hours/day = 2 days

Verification: Bell 1: 483 = 16 comp<=te cyc<=s Bell 2: 484 = 12 comp<=te cyc<=s Bell 3: 4816 = 3 comp<=te cyc<=s All bells comp<=te their cyc<=s perfectly in 48 hours. The bells will ring to>=ther again after 2 days."}],["$","meta","9",{"property":"og:url","content":"/past-year-questions/iimk-bmsat/2025/QA/43"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IIM-K (BMSAT) 2025 Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"IIM-K (BMSAT) 2025 - 3 bells ring at intervals of 3hrs, 4hrs and 16hrs respectively. If they have rung together once today, what day in the future will they ring together next? | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined We need to find when all 3 bells will ring at the same time again. This happens at the LCM (Least Common Multip<=) of their intervals.

Convert to days: 48 hours24 hours/day = 2 days

Verification: Bell 1: 483 = 16 comp<=te cyc<=s Bell 2: 484 = 12 comp<=te cyc<=s Bell 3: 4816 = 3 comp<=te cyc<=s All bells comp<=te their cyc<=s perfectly in 48 hours. The bells will ring to>=ther again after 2 days."}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

IIM-K (BMSAT) 2025 (QA) PYQs

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