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If 2n=1024\sqrt{2^n} = 1024, then 3(n/4−4)3^{(n/4 - 4)} is = ?

Solution

✅ Correct Option: 2

2n=2n/2\sqrt{2^n} = 2^{n/2} and 1024=2101024 = 2^{10}

So, 2n/2=2102^{n/2} = 2^{10}

n2=10\frac{n}{2} = 10

n=20n = 20


3(n/4−4)=3(20/4−4)3^{(n/4 - 4)} = 3^{(20/4 - 4)}

=3(5−4)= 3^{(5 - 4)}

=31= 3^1

=3= 3

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