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Water flows at the rate of 55 km/hr through a pipe of diameter 1414 cm into a rectangular tank that is 5050 m long and 4444 m wide. Determine the time in which the level of the water in the tank will rise by 77 cm.

(Assume π=22/7\pi = 22/7)

Solution

✅ Correct Option: 3

Pipe diameter = 1414 cm, so radius = 142=7\dfrac{14}{2} = 7 cm

Area of circular pipe = πr2\pi r^2

=227×72= \dfrac{22}{7} \times 7^2

=227×49= \dfrac{22}{7} \times 49

=22×7= 22 \times 7

=154= 154 cm²


Water speed = 55 km/hr

=5×1000×100= 5 \times 1000 \times 100

=500,000= 500,000 cm/hr


Volume flow rate = Area × Speed

=154×500,000= 154 \times 500,000

=77,000,000= 77,000,000 cm³/hr


Tank dimensions:

Length = 5050 m = 50005000 cm

Width = 4444 m = 44004400 cm

Height rise needed = 77 cm

Volume needed = 5000×4400×75000 \times 4400 \times 7

=154,000,000= 154,000,000 cm³


Time = Volume neededVolume flow rate\dfrac{\text{Volume needed}}{\text{Volume flow rate}}

=154,000,00077,000,000= \dfrac{154,000,000}{77,000,000}

=15477= \dfrac{154}{77}

=2= 2 hours

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