Q1:

BMSAT Kozhikode 2025

Identities

Medium

If x=283x = \sqrt[3]{28} and y=273y = \sqrt[3]{27}, find the value of x+y−1x2+xy+y2x + y - \frac{1}{x^2+xy+y^2}.

Answer options
Option 2
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 1

Q2:

BMSAT Kozhikode 2025

Identities

Medium

Say y=32−4y = 3\sqrt{2} - 4, find y2+1y2y^2 + \frac{1}{y^2}.

Answer options
Option 3
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 2

Q3:

BMSAT Kozhikode 2025

Identities

Medium

If x2+1x2=83x^{2}+\frac{1}{x^{2}}=83 and x>1x>1, then the value of x3−1x3x^{3}-\frac{1}{x^{3}} is

Answer options
Option 2
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 3