BMSAT KozhikodeAlgebra > Mediuma>b<ca > b < ca>b<ca<b<ca < b < ca<b<caca caca>b>ca > b > ca>b>c✅ Correct Option: 4Related questions:2026If 2n=1024\sqrt{2^n} = 10242n=1024, then 3(n/4−4)3^{(n/4 - 4)}3(n/4−4) is = ?2026If 2x/(1+2x)=1/32^x/(1 + 2^x) = 1/32x/(1+2x)=1/3, then 8x/(1−8x)=?8^x/(1-8^x) = ?8x/(1−8x)=?2026If 2n+m/(2n−m)=162^{n+m}/(2^{n-m}) = 162n+m/(2n−m)=16 and a=21/10a = 2^{1/10}a=21/10, then, (a2m+n−p)2/(am−2n+2p)−1=?(a^{2m+n-p})^2/(a^{m-2n+2p})^{-1} = ?(a2m+n−p)2/(am−2n+2p)−1=?