What's the area of the quadrilateral included inside the points: $(-1, 2), (-1, 4), (7, 2), (7, 4)?$

The given points are:

• Point A: $(-1, 2)$
• Point B: $(-1, 4)$
• Point C: $(7, 2)$
• Point D: $(7, 4)$

Points A and B share $x = -1$, while points C and D share $x = 7$.

Points A and C share $y = 2$, while points B and D share $y = 4$.

These points form a rectangle.

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Width (horizontal distance):

$\text{Width} = 7 - (-1)$

$\text{Width} = 8$ units

Height (vertical distance):

$\text{Height} = 4 - 2$

$\text{Height} = 2$ units

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Area $= \text{Width} \times \text{Height}$

Area $= 8 \times 2$

Area $= 16$ square units

Therefore, the area of the quadrilateral is $16$ square units.