If $360 = 2^x \times 3^y \times 5^z$, then $x+y+z=?$

The prime factorization of $360$ can be found by dividing by the smallest prime numbers:

$360 \div 2 = 180$

$180 \div 2 = 90$

$90 \div 2 = 45$

$45 \div 3 = 15$

$15 \div 3 = 5$

$5 \div 5 = 1$

Therefore:

$360 = 2^3 \times 3^2 \times 5^1$

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Comparing with the given form $360 = 2^x \times 3^y \times 5^z$:

$x = 3$

$y = 2$

$z = 1$

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$x + y + z = 3 + 2 + 1$

$x + y + z = 6$