9:{"metadata":[["$","title","0",{"children":"IIM-K (BMSAT) 2025 - The ratio of alcohol to water in two containers, A and B, are 5:3 and 1:3, respectively, with both containers having infinite capacity. Suppose that the aim is to obtain 2.1 litre of liquid which is composed of equal quantities of alcohol and water. How much liquid should be drawn from A? | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined We need 2.1 liters of liquid with equal amounts of alcohol and water (that means 1.05 liters alcohol + 1.05 liters water). Container A: Ratio 5:3 (alcohol:water) = 5 parts alcohol, 3 parts water = 8 total parts Container B: Ratio 1:3 (alcohol:water) = 1 part alcohol, 3 parts water = 4 total parts

Container A: Alcohol makes up 58 of the liquid Container B: Alcohol makes up 14 of the liquid

Let x = liters drawn from container A Then (2.1 - x) = liters drawn from container B

We need exactly 1.05 liters of alcohol total. Alcohol from A + Alcohol from B = 1.05 liters 58x + 14(2.1 - x) = 1.05

58x + 14(2.1) - 14x = 1.05 58x + 0.525 - 14x = 1.05 58x - 28x = 1.05 - 0.525 38x = 0.525 x = 0.525 83 = 1.4

From A (1.4 liters): Alcohol = 58 1.4 = 0.875 liters From B (0.7 liters): Alcohol = 14 0.7 = 0.175 liters Total alcohol: 0.875 + 0.175 = 1.05 liters ✓ Total water: 1.4 - 0.875 + 0.7 - 0.175 = 1.05 liters ✓

1.4 liters should be drawn from container A"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"IIM-K (BMSAT),QA,Arithmetic,Mixture & Alligation"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"IIM-K (BMSAT) 2025 - The ratio of alcohol to water in two containers, A and B, are 5:3 and 1:3, respectively, with both containers having infinite capacity. Suppose that the aim is to obtain 2.1 litre of liquid which is composed of equal quantities of alcohol and water. How much liquid should be drawn from A? | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined We need 2.1 liters of liquid with equal amounts of alcohol and water (that means 1.05 liters alcohol + 1.05 liters water). Container A: Ratio 5:3 (alcohol:water) = 5 parts alcohol, 3 parts water = 8 total parts Container B: Ratio 1:3 (alcohol:water) = 1 part alcohol, 3 parts water = 4 total parts

Container A: Alcohol makes up 58 of the liquid Container B: Alcohol makes up 14 of the liquid

Let x = liters drawn from container A Then (2.1 - x) = liters drawn from container B

We need exactly 1.05 liters of alcohol total. Alcohol from A + Alcohol from B = 1.05 liters 58x + 14(2.1 - x) = 1.05

58x + 14(2.1) - 14x = 1.05 58x + 0.525 - 14x = 1.05 58x - 28x = 1.05 - 0.525 38x = 0.525 x = 0.525 83 = 1.4

1.4 liters should be drawn from container A"}],["$","meta","9",{"property":"og:url","content":"/past-year-questions/iimk-bmsat/2025/QA/12"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IIM-K (BMSAT) 2025 Preparation"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21","$L22","$L23","$L24","$L25","$L26","$L27"],"error":null,"digest":"$undefined"}

IIM-K (BMSAT) 2025 (QA) PYQs

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