BMSAT KozhikodeAlgebra > Medium21/202^{1/20}21/201/2Cannot be found2✅ Correct Option: 4Related questions:BMSAT Kozhikode 2025If x112=49124x^{\frac{1}{12}}=49^{\frac{1}{24}}x121=49241, the value of xxx is:2026If 2n=1024\sqrt{2^n} = 10242n=1024, then 3(n/4−4)3^{(n/4 - 4)}3(n/4−4) is = ?2026If 2x/(1+2x)=1/32^x/(1 + 2^x) = 1/32x/(1+2x)=1/3, then 8x/(1−8x)=?8^x/(1-8^x) = ?8x/(1−8x)=?