Q1:

BMSAT Kozhikode 2026

Trigonometry

Easy

If a pole is 6 meters high and casts a shadow 232\sqrt{3} meters long on the ground, then the sun's elevation is

Answer options
Option 4
Correct Answer
Explanation for BMSAT Kozhikode 2026 QA question 1

Q2:

BMSAT Kozhikode 2026

Trigonometry

Medium

If cos⁡α+cos⁡β+cos⁡γ=3\cos\alpha + \cos\beta + \cos\gamma = 3, then cos⁡3α+cos⁡3β+cos⁡3γ\cos^3\alpha + \cos^3\beta + \cos^3\gamma will be

Answer options
Option 3
Correct Answer
Explanation for BMSAT Kozhikode 2026 QA question 2

Q3:

BMSAT Kozhikode 2026

Trigonometry

Medium

In △ABC\triangle ABC, ∠A=90∘\angle A = 90^{\circ}, if tan⁡C=3\tan C = \sqrt{3}, then find the value of sin⁡B+cos⁡C−cos⁡2B\sin B + \cos C - \cos^2 B

Answer options
Option 2
Correct Answer
Explanation for BMSAT Kozhikode 2026 QA question 3

Q4:

BMSAT Kozhikode 2025

Trigonometry

Medium

If 1+sin⁡2θ=3sin⁡θcos⁡θ1 + \sin^2\theta = 3 \sin \theta \cos \theta, then tan⁡θ\tan \theta can take values

Answer options
Option 1
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 4

Q5:

BMSAT Kozhikode 2025

Trigonometry

Easy

If a pole 6 m high casts a shadow 232\sqrt{3} m long on the ground, then the sun's elevation is

Answer options
Option 1
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 5

Q6:

BMSAT Kozhikode 2025

Trigonometry

Easy

sin⁡θ(1+cos⁡θ)\dfrac{\sin \theta}{(1+ \cos \theta)} is equal to

Answer options
Option 3
Correct Answer
Explanation for BMSAT Kozhikode 2025 QA question 6