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Match List-I with List-II

List-IList-II
Differential EquationSum of order and degree
(A) d2ydx2+dydx+3y=sin⁡x\frac{d^2y}{dx^2} + \frac{dy}{dx} + 3y = \sin x(I) 2
(B) dydx=sin⁡(x+y)\frac{dy}{dx} = \sin(x + y)(II) 3
(C) 1+(dydx)2=d2ydx2\sqrt{1 + (\frac{dy}{dx})^2} = \frac{d^2y}{dx^2}(III) 4
(D) x2(d2ydx2)3+y(dydx)4+y5=0x^2(\frac{d^2y}{dx^2})^3 + y(\frac{dy}{dx})^4 + y^5 = 0(IV) 5

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Order is the highest derivative in the equation. Degree is the power of the highest order derivative after removing all roots and fractions involving derivatives.


(A) d2ydx2+dydx+3y=sin⁡x\frac{d^2y}{dx^2} + \frac{dy}{dx} + 3y = \sin x

Highest derivative is d2ydx2\frac{d^2y}{dx^2}

Order =2= 2

Power of d2ydx2\frac{d^2y}{dx^2} is 11

Degree =1= 1

Sum =2+1=3= 2 + 1 = 3

Matches with (II)


(B) dydx=sin⁡(x+y)\frac{dy}{dx} = \sin(x + y)

Highest derivative is dydx\frac{dy}{dx}

Order =1= 1

Power of dydx\frac{dy}{dx} is 11

Degree =1= 1

Sum =1+1=2= 1 + 1 = 2

Matches with (I)


(C) 1+(dydx)2=d2ydx2\sqrt{1 + (\frac{dy}{dx})^2} = \frac{d^2y}{dx^2}

Highest derivative is d2ydx2\frac{d^2y}{dx^2}

Order =2= 2

The equation contains a square root, so it must be removed:

1+(dydx)2=(d2ydx2)21 + (\frac{dy}{dx})^2 = (\frac{d^2y}{dx^2})^2

Power of d2ydx2\frac{d^2y}{dx^2} is 22

Degree =2= 2

Sum =2+2=4= 2 + 2 = 4

Matches with (III)


(D) x2(d2ydx2)3+y(dydx)4+y5=0x^2(\frac{d^2y}{dx^2})^3 + y(\frac{dy}{dx})^4 + y^5 = 0

Highest derivative is d2ydx2\frac{d^2y}{dx^2}

Order =2= 2

Power of d2ydx2\frac{d^2y}{dx^2} is 33

Degree =3= 3

Sum =2+3=5= 2 + 3 = 5

Matches with (IV)


Final Matching:

(A) → (II)

(B) → (I)

(C) → (III)

(D) → (IV)

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