CUET Mathematics - Match **List-I** with **List-II** | List-I | List-II | |---|---| | **Differential Equation** | **Sum of order and degree** | | (A) d^2y/dx^2 + dy/dx + 3y = x | (I) 2 | | (B) dy/dx = (x + y) | (II) 3 | | (C) sqrt(1 + (dy/dx)^2) = d^2y/dx^2 | (III) 4 | | (D) x^2(d^2y/dx^2)^3 + y(dy/dx)^4 + y^5 = 0 | (IV) 5 | Choose the **correct** answer from the options given below: | PYQs + Solutions

CUET Mathematics 2025 3 June Shift 1

Calculus

Medium

applied

(A) - (II), (B) - (I), (C) - (IV), (D) - (III)

(A) - (II), (B) - (I), (C) - (III), (D) - (IV)

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

✅ Correct Option: 2

Related questions:

3 June Shift 1

If m and n are respectively the order and degree of the differential equation $(y^2\frac{d^2y}{dx^2})^{3/4} + (\frac{dy}{dx})^4 = 0$ , then the value of $m + n$ is:

3 June Shift 1

Consider the differential equation $xdy = (y + 2x^2)dx$ . Then which of the following are TRUE?

(A) It is a homogeneous differential equation.

(B) Product of the order and degree of the differential equation in one.

(D) General solution of the differential equation is $y = x^3 + Cx$ , where C is an arbitary constant.

Choose the correct answer from the options given below:

14 May Shift 2

Particular solution of the differential equation $x(1 + y^2)dx - y(1 + x^2)dy = 0$ , given $y = 0$ when $x = 1$ , is

CUET Mathematics 2025 3 June Shift 1 PYQs

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