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If ddx[ax3+ax2+ax+1]=9x2+6x+3\frac{d}{dx}[ax^3 + ax^2 + ax + 1] = 9x^2 + 6x + 3, then aa is equal to

Solution

✅ Correct Option: 3

Given that the derivative of ax3+ax2+ax+1ax^3 + ax^2 + ax + 1 equals 9x2+6x+39x^2 + 6x + 3.

Differentiating ax3+ax2+ax+1ax^3 + ax^2 + ax + 1 term by term:

ddx[ax3]=3ax2\frac{d}{dx}[ax^3] = 3ax^2

ddx[ax2]=2ax\frac{d}{dx}[ax^2] = 2ax

ddx[ax]=a\frac{d}{dx}[ax] = a

ddx[1]=0\frac{d}{dx}[1] = 0

The derivative is 3ax2+2ax+a3ax^2 + 2ax + a


Setting the derivative equal to the given expression:

3ax2+2ax+a=9x2+6x+33ax^2 + 2ax + a = 9x^2 + 6x + 3


For two polynomials to be equal, coefficients of corresponding powers must be equal.

Comparing coefficients of x2x^2:

3a=93a = 9

a=3a = 3

Comparing coefficients of xx:

2a=62a = 6

a=3a = 3

Comparing constant terms:

a=3a = 3


Therefore, a=3a = 3

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