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Let P and Q be any two invertible matrices of the same order. Then

Match List-I with List-II

List-IList-II
MatrixEquivalent matrix
(A) (PQ)−1(P Q)^{-1}(I) Q−1PQ^{-1}P
(B) (P−1Q)−1(P^{-1}Q)^{-1}(II) QP−1Q P^{-1}
(C) (PQ−1)−1(P Q^{-1})^{-1}(III) Q−1P−1Q^{-1}P^{-1}
(D) (P−1Q−1)−1(P^{-1}Q^{-1})^{-1}(IV) Q P

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

For finding the inverse of a product of matrices, reverse the order and invert each matrix:

(AB)−1=B−1A−1(AB)^{-1} = B^{-1}A^{-1}


For (PQ)−1(PQ)^{-1}:

(PQ)−1=Q−1P−1(PQ)^{-1} = Q^{-1}P^{-1}

This matches (III)


For (P−1Q)−1(P^{-1}Q)^{-1}:

(P−1Q)−1=Q−1(P−1)−1(P^{-1}Q)^{-1} = Q^{-1}(P^{-1})^{-1}

=Q−1P= Q^{-1}P

This matches (I)


For (PQ−1)−1(PQ^{-1})^{-1}:

(PQ−1)−1=(Q−1)−1P−1(PQ^{-1})^{-1} = (Q^{-1})^{-1}P^{-1}

=QP−1= QP^{-1}

This matches (II)


For (P−1Q−1)−1(P^{-1}Q^{-1})^{-1}:

(P−1Q−1)−1=(Q−1)−1(P−1)−1(P^{-1}Q^{-1})^{-1} = (Q^{-1})^{-1}(P^{-1})^{-1}

=QP= QP

This matches (IV)


The matching is:

(A) → (III)

(B) → (I)

(C) → (II)

(D) → (IV)

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