CUET Mathematics 2025 3 June Shift 1 PYQs

$\int_0^{\pi/2} \sqrt{1 - \sin 2x}\,dx$ is equal to:

The value of the definite integral $I = \int_{-1}^{1} \frac{1}{1 + \sqrt{e^x}} dx$ is:

$\int_0^{\pi/2} \frac{\sin^8 x}{\sin^8 x + \cos^8 x} dx$ is equal to