Skip to main contentSkip to solution

The edge of a cube is increasing at a rate of 7cm/s. The rate of change of area of the cube when edge of the cube is 3cm is:

Solution

✅ Correct Option: 4

The edge of a cube is increasing at a rate of 77 cm/s, so dadt=7\frac{da}{dt} = 7 cm/s.

The edge length at this moment is a=3a = 3 cm.


A cube has 6 faces, each face is a square with area a2a^2.

Surface Area A=6a2A = 6a^2


Differentiating both sides with respect to time tt:

dAdt=6×2a×dadt\frac{dA}{dt} = 6 \times 2a \times \frac{da}{dt}

dAdt=12a×dadt\frac{dA}{dt} = 12a \times \frac{da}{dt}


Substituting a=3a = 3 cm and dadt=7\frac{da}{dt} = 7 cm/s:

dAdt=12×3×7\frac{dA}{dt} = 12 \times 3 \times 7

dAdt=36×7\frac{dA}{dt} = 36 \times 7

dAdt=252\frac{dA}{dt} = 252 cm²/s

Therefore, the rate of change of surface area of the cube is 252252 cm²/s.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question