If y = _e( e^x^2) then dy/dx = Option 1: x^2e^x^2 e^x^2 Option 2: 2xe^x^2 e^x^2 Option 3: e^x^2 e^x^2 Option 4: xe^x^2 e^x^2

The answer is '2xe^x^2 e^x^2'. View full solution:

Calculus > Continuity & Differentiability

Medium

core

If $y = \log_e(\sec e^{x^2})$ then $\frac{dy}{dx} =$

$x^2e^{x^2} \tan e^{x^2}$

$2xe^{x^2} \tan e^{x^2}$

$e^{x^2} \tan e^{x^2}$

$xe^{x^2} \tan e^{x^2}$

✅ Correct Option: 2

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