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If A and B are independent events, then which of the following is not true?

Solution

✅ Correct Option: 4

Independent events occur when one event happening doesn't affect the other event's probability.

For independent events A and B: P(A∩B)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)

Mutually exclusive events cannot happen at the same time.

For mutually exclusive events: P(A∩B)=0P(A \cap B) = 0


Option 4 states that A and B are mutually exclusive. This is NOT true.

If A and B are both independent AND mutually exclusive:

P(A∩B)=P(A)×P(B)P(A \cap B) = P(A) \times P(B) (from independence)

P(A∩B)=0P(A \cap B) = 0 (from mutual exclusivity)

Therefore: P(A)×P(B)=0P(A) \times P(B) = 0

This means either P(A)=0P(A) = 0 or P(B)=0P(B) = 0, implying one event is impossible.

For typical events with non-zero probabilities, independent events are NOT mutually exclusive.


Option 1: A′A' and B′B' are independent.

When A and B are independent, their complements are also independent.

P(A′∩B′)=P(A′)×P(B′)P(A' \cap B') = P(A') \times P(B')

This statement is true.


Option 2: A and B′B' are independent.

When A and B are independent, A and the complement of B are also independent.

P(A∩B′)=P(A)×P(B′)P(A \cap B') = P(A) \times P(B')

This statement is true.


Option 3: A′A' and B are independent.

When A and B are independent, the complement of A and B are also independent.

P(A′∩B)=P(A′)×P(B)P(A' \cap B) = P(A') \times P(B)

This statement is true.


Option 4 is the correct answer.

Independent events can occur together, while mutually exclusive events cannot. These are fundamentally different concepts.

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