CUET Mathematics - If the difference between mean and variance of a Binomial distribution is 1 and the difference of their squares is 5, then the probability of success is | PYQs + Solutions

CUET Mathematics 2025 3 June Shift 1

Algebra

Medium

applied

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{2}{5}$

$\frac{3}{5}$

✅ Correct Option: 2

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A player participates in 3 matches against three teams T₁, T₂ and T₃.The probability of winning a match against teams T₁, T₂ and T₃ are 0.2, 0.3 and 0.9 respectively. If 'wins' can be regarded as independent events, then the probability that he

(A) wins all the 3 matches is 0.054

(B) wins no match is 0.054

(D) wins exactly one match is 0.542

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If $2P(A) = P(B) = \frac{5}{13}$ and $P(A|B) = \frac{2}{5}$ , then $P(A \cap B)$ is

CUET Mathematics 2025 3 June Shift 1 PYQs

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