Area of the region bounded by the curve $y = \sin x$ and x-axis between $x = \frac{\pi}{2}$ and $x = \frac{3\pi}{2}$ is

The area of the smaller region of the circle $x^2 + y^2 = 8$ cut off by the line $x = 2$ is

The area of the region bounded by the curves $y = 1+|x-1|, x=-1, x=2, y=0$ is

The value of $x$ for which $\frac{dy}{dx} = 0$, is

The area of the region enclosed between the curves $4 x^{2}=y$ and $y=4$ is :

The area bounded by the curve $y = 4 + 3x - x^2$ and $x$-axis is equal to

The area of region bounded by the curve $y^2 = 4ax$ and the straight line $x = 2a$, $a > 0$ in the first quadrant is: