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The corner points of the bounded feasible region of an LPP are (0,0), (6,0), (4,3) and (0,6). Let Z=ax+byZ = ax + by, where a,b>0a, b > 0. Condition on aa and bb so that the maximum of ZZ occurs at both (4, 3) and (0, 6) is

Solution

✅ Correct Option: 3

If the maximum occurs at two corner points, ZZ has equal values there. So Z(4,3)=Z(0,6)Z(4,3)=Z(0,6) gives 4a+3b=6b4a+3b=6b, i.e. 4a=3b4a=3b.

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