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The system of linear equations kx+5y=5kx + 5y = 5, 2x+3y=52x + 3y = 5 will be consistent if

Solution

✅ Correct Option: 3

For the system of linear equations kx+5y=5kx + 5y = 5 and 2x+3y=52x + 3y = 5 to be consistent, it must have at least one solution. A system is inconsistent when the lines are parallel but distinct (no solution).

For two equations a1x+b1y=c1a_1x + b_1y = c_1 and a2x+b2y=c2a_2x + b_2y = c_2, the system is inconsistent when:

a1a2=b1b2≠c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}


From the given equations:

a1=ka_1 = k, b1=5b_1 = 5, c1=5c_1 = 5

a2=2a_2 = 2, b2=3b_2 = 3, c2=5c_2 = 5

The ratios are:

a1a2=k2\frac{a_1}{a_2} = \frac{k}{2}

b1b2=53\frac{b_1}{b_2} = \frac{5}{3}

c1c2=55=1\frac{c_1}{c_2} = \frac{5}{5} = 1


The system is inconsistent when:

k2=53\frac{k}{2} = \frac{5}{3} and k2≠1\frac{k}{2} \neq 1

k2=53\frac{k}{2} = \frac{5}{3}

k=103k = \frac{10}{3}

Since 10/32=53≠1\frac{10/3}{2} = \frac{5}{3} \neq 1, the condition is satisfied.


The system is consistent for all values of kk except when the lines are parallel and distinct.

Therefore, the system is consistent when k≠103k \neq \frac{10}{3}

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