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The sides of an equilateral triangle are increasing at the rate of 5 cm/sec. The rate at which the area increases when the side is 20 cm, is

Solution

✅ Correct Option: 2

The sides of an equilateral triangle are increasing at the rate of 5 cm/sec, with the current side length at 20 cm.

The area of an equilateral triangle with side aa is given by:

A=34×a2A = \dfrac{\sqrt{3}}{4} \times a^2


Differentiating both sides with respect to time tt:

dAdt=34×d(a2)dt\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{4} \times \dfrac{d(a^2)}{dt}

dAdt=34×2a×dadt\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{4} \times 2a \times \dfrac{da}{dt}

dAdt=32×a×dadt\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{2} \times a \times \dfrac{da}{dt}


Given:

a=20a = 20 cm

dadt=5\dfrac{da}{dt} = 5 cm/sec

Substituting the values:

dAdt=32×20×5\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{2} \times 20 \times 5

dAdt=32×100\dfrac{dA}{dt} = \dfrac{\sqrt{3}}{2} \times 100

dAdt=503\dfrac{dA}{dt} = 50\sqrt{3} cm²/sec

Therefore, the rate at which the area increases is 50350\sqrt{3} cm²/sec.

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